Execute bash command in Node.js and get exit code

Those 2 commands are running in separate shells.

To get the code, you should be able to check err.code in your callback.

If that doesn't work, you need to add an exit event handler

e.g.

dir = exec("ls -la", function(err, stdout, stderr) {  if (err) {    // should have err.code here?    }  console.log(stdout);});dir.on('exit', function (code) {  // exit code is code});

From the docs:

If a callback function is provided, it is called with the arguments (error, stdout, stderr). On success, error will be null. On error, error will be an instance of Error. The error.code property will be the exit code of the child process while error.signal will be set to the signal that terminated the process. Any exit code other than 0 is considered to be an error.

So:

exec('...', function(error, stdout, stderr) {  if (error) {    console.log(error.code);  }});

Should work.

child_process.spawnSync()

This function exposes the nicest sync interface: https://nodejs.org/api/child_process.html#child_process_child_process_spawnsync_command_args_options

Example:

#!/usr/bin/env nodeconst child_process = require('child_process');let out;out = child_process.spawnSync('true');console.log('status: ' + out.status);console.log('stdout: ' + out.stdout.toString('utf8'));console.log('stderr: ' + out.stderr.toString('utf8'));console.log();out = child_process.spawnSync('false');console.log('status: ' + out.status);console.log('stdout: ' + out.stdout.toString('utf8'));console.log('stderr: ' + out.stderr.toString('utf8'));console.log();out = child_process.spawnSync('echo', ['abc']);console.log('status: ' + out.status);console.log('stdout: ' + out.stdout.toString('utf8'));console.log('stderr: ' + out.stderr.toString('utf8'));console.log();

Output:

status: 0stdout: stderr: status: 1stdout: stderr: status: 0stdout: abcstderr: 

Tested in Node.js v10.15.1, Ubuntu 19.10.