exit with error message in bash (oneline) exit with error message in bash (oneline) bash bash

exit with error message in bash (oneline)


bash message exit

exit doesn't take more than one argument. To print any message like you want, you can use echo and then exit.

    [[ $TRESHOLD =~ ^[0-9]+$ ]] || \     { echo "Threshold must be an integer value!"; exit $ERRCODE; }

bash message exit

You can use a helper function:

function fail {    printf '%s\n' "$1" >&2  ## Send message to stderr. Exclude >&2 if you don't want it that way.    exit "${2-1}"  ## Return a code specified by $2 or 1 by default.}[[ $TRESHOLD =~ ^[0-9]+$ ]] || fail "Threshold must be an integer value!"

Function name can be different.

bash message exit

Using exit directly may be tricky as the script may be sourced from other places. I prefer instead using subshell with set -e (plus errors should go into cerr, not cout) :

set -e[[ $TRESHOLD =~ ^[0-9]+$ ]] || \     (>&2 echo "Threshold must be an integer value!"; exit $ERRCODE)

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