How can I compare a string to multiple correct values in Bash?
If the main intent is to check whether the supplied value is not found in a list, maybe you can use the extended regular expression matching built in BASH via the "equal tilde" operator (see also this answer):
if ! [[ "$cms" =~ ^(wordpress|meganto|typo3)$ ]]; then get_cms ; fiHave a nice day
Instead of saying:
if [ "$cms" != "wordpress" && "$cms" != "meganto" && "$cms" != "typo3" ]; thensay:
if [[ "$cms" != "wordpress" && "$cms" != "meganto" && "$cms" != "typo3" ]]; thenYou might also want to refer to Conditional Constructs.
Maybe you should better use a case for such lists:
case "$cms" in wordpress|meganto|typo3) do_your_else_case ;; *) do_your_then_case ;;esacI think for long such lists this is better readable.
If you still prefer the if you can do it with single brackets in two ways:
if [ "$cms" != wordpress -a "$cms" != meganto -a "$cms" != typo3 ]; thenor
if [ "$cms" != wordpress ] && [ "$cms" != meganto ] && [ "$cms" != typo3 ]; then