How can I detect DOS line breaks in a file?

Python can automatically detect what newline convention is used in a file, thanks to the "universal newline mode" (U), and you can access Python's guess through the newlines attribute of file objects:

f = open('myfile.txt', 'U')f.readline()  # Reads a line# The following now contains the newline ending of the first line:# It can be "\r\n" (Windows), "\n" (Unix), "\r" (Mac OS pre-OS X).# If no newline is found, it contains None.print repr(f.newlines)

This gives the newline ending of the first line (Unix, DOS, etc.), if any.

As John M. pointed out, if by any chance you have a pathological file that uses more than one newline coding, f.newlines is a tuple with all the newline codings found so far, after reading many lines.

Reference: http://docs.python.org/2/library/functions.html#open

If you just want to convert a file, you can simply do:

with open('myfile.txt', 'U') as infile:    text = infile.read()  # Automatic ("Universal read") conversion of newlines to "\n"with open('myfile.txt', 'w') as outfile:    outfile.write(text)  # Writes newlines for the platform running the program

You could search the string for \r\n. That's DOS style line ending.

EDIT: Take a look at this

(Python 2 only:) If you just want to read text files, either DOS or Unix-formatted, this works:

print open('myfile.txt', 'U').read()

That is, Python's "universal" file reader will automatically use all the different end of line markers, translating them to "\n".

http://docs.python.org/library/functions.html#open

(Thanks handle!)