how to use xargs with sed in search pattern

bash sed replace pipeline

You need to tell xargs what to replace with the -I switch - it doesn't seem to know about the {} automatically, at least in some versions.

echo "pattern" | xargs -I '{}' sed -i 's/{}/replacement/g' file.txt

bash sed replace pipeline

this works on Linux(tested):

find . -type f -print0 | xargs -0 sed -i 's/str1/str2/g'

bash sed replace pipeline

Use command substitution instead, so your example would look like:

sed -i "s/$(echo "some pattern")/replacement/g" file.txt

The double quotes allow for the command substitution to work while preventing spaces from being split.

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