Is there a way to make bash job control quiet?

You can use parentheses to run a background command in a subshell, and that will silence the job control messages. For example:

(sleep 10 & )

^{Note: The following applies to interactive Bash sessions. In scripts, job-control messages are never printed.}

There are 2 basic scenarios for silencing Bash's job-control messages:

Launch-and-forget:

CodeGnome's helpful answer answer suggests enclosing the background command in a simple subshell - e.g, (sleep 10 &) - which effectively silences job-control messages - both on job creation and on job termination.

This has an important side effect:

• By using control operator & inside the subshell, you lose control of the background job - jobs won't list it, and neither %% (the spec. (ID) of the most recently launched job) nor $! (the PID of the (last) process launched (as part of) the most recent job) will reflect it.^[1]

For launch-and-forget scenarios, this is not a problem:

• You just fire off the background job,
• and you let it finish on its own (and you trust that it runs correctly).

^{[1] Conceivably, you could go looking for the process yourself, by searching running processes for ones matching its command line, but that is cumbersome and not easy to make robust.}

Launch-and-control-later:

If you want to remain in control of the job, so that you can later:

• kill it, if need be.
• synchronously wait (at some later point) for its completion,

a different approach is needed:

• Silencing the creation job-control messages is handled below, but in order to silence the termination job-control messages categorically, you must turn the job-control shell option OFF:

  • set +m (set -m turns it back on)
  • Caveat: This is a global setting that has a number of important side effects, notably:
    • Stdin for background commands is then /dev/null rather than the current shell's.
    • The keyboard shortcuts for suspending (Ctrl-Z) and delay-suspending (Ctrl-Y) a foreground command are disabled.
    • For the full story, see man bash and (case-insensitively) search for occurrences of "job control".

• To silence the creation job-control messages, enclose the background command in a group command and redirect the latter's stderr output to /dev/null

  { sleep 5 & } 2>/dev/null

The following example shows how to quietly launch a background job while retaining control of the job in principle.

$ set +m; { sleep 5 & } 2>/dev/null # turn job-control option off and launch quietly$ jobs # shows the job just launched; it will complete quietly due to set +m 

If you do not want to turn off the job-control option (set +m), the only way to silence the termination job-control message is to either kill the job or wait for it:

Caveat: There are two edge cases where this technique still produces output:

• If the background command tries to read from stdin right away.
• If the background command terminates right away.

To launch the job quietly (as above, but without set +m):

$ { sleep 5 & } 2>/dev/null

To wait for it quietly:

$ wait %% 2>/dev/null    # use of %% is optional here

To kill it quietly:

{ kill %% && wait; } 2>/dev/null

The additional wait is necessary to make the termination job-control message that is normally displayed asynchronously by Bash (at the time of actual process termination, shortly after the kill) a synchronous output from wait, which then allows silencing.

But, as stated, if the job completes by itself, a job-control message will still be displayed.

Wrap it in a dummy script:

quiet.sh:

#!/bin/bash$@ &

then call it, passing your command to it as an argument:

./quiet.sh echo toto

You may need to play with quotes depending on your input.