Jenkins delete builds older than latest 20 builds for all jobs

You can use the Jenkins Script Console to iterate through all jobs, get a list of the N most recent and perform some action on the others.

import jenkins.model.Jenkinsimport hudson.model.JobMAX_BUILDS = 20for (job in Jenkins.instance.items) {  println job.name  def recent = job.builds.limit(MAX_BUILDS)  for (build in job.builds) {    if (!recent.contains(build)) {      println "Preparing to delete: " + build      // build.delete()    }  }}

The Jenkins Script Console is a great tool for administrative maintenance like this and there's often an existing script that does something similar to what you want.

I got an issue No such property: builds for class: com.cloudbees.hudson.plugins.folder.Folder on Folders Plugin 6.6 while running @Dave Bacher's script

Alter it to use functional api

import jenkins.model.Jenkinsimport hudson.model.JobMAX_BUILDS = 5Jenkins.instance.getAllItems(Job.class).each { job ->  println job.name  def recent = job.builds.limit(MAX_BUILDS)  for (build in job.builds) {    if (!recent.contains(build)) {      println "Preparing to delete: " + build      build.delete()    }  }}

There are lots of ways to do this

Personally I would use the 'discard old builds' in the job config

If you have lots of jobs you could use the CLI to step through all the jobs to add it

Alternatively there is the configuration slicing plugin which will also do this for you on a large scale