Passing parameters to bash when executing a script fetched by curl

To improve on jinowolski's answer a bit, you should use:

curl http://example.com/script.sh | bash -s -- arg1 arg2

Notice the two dashes (--) which are telling bash to not process anything following it as arguments to bash.

This way it will work with any kind of arguments, e.g.:

curl -L http://bootstrap.saltstack.org | bash -s -- -M -N stable

This will of course work with any kind of input via stdin, not just curl, so you can confirm that it works with simple BASH script input via echo:

echo 'i=1; for a in $@; do echo "$i = $a"; i=$((i+1)); done' | \bash -s -- -a1 -a2 -a3 --long some_text

Will give you the output

1 = -a12 = -a23 = -a34 = --long5 = some_text

try

curl http://foo.com/script.sh | bash -s arg1 arg2

bash manual says:

If the -s option is present, or if no arguments remain after option processing, then commands are read from the standard input. This option allows the positional parameters to be set when invoking an interactive shell.

Other alternatives:

curl http://foo.com/script.sh | bash /dev/stdin argumentsbash <( curl http://foo.com/script.sh ) arguments