Pretend to be a tty in bash for any command [duplicate]
There are a number of options, as outlined by several other Stack Overflow answers (see Caarlos's comment). I'll summarize them here though:
Use
script+printf, requires no extra dependencies:0<&- script -qefc "ls --color=auto" /dev/null | catOr make a bash function
fakettyto encapsulate it:faketty () { script -qfce "$(printf "%q " "$@")" } faketty ls --color=auto | catOr in the fish shell:
function faketty script -qefc "(printf "%q " "$argv")" end faketty ls --color=auto | cat(credit goes to this answer)
Use the
unbuffercommand (as part of theexpectsuite of commands), unfortunately this requires an extra package install, but it's the easiest solution:sudo apt-get install expect-dev unbuffer -p ls --color=auto | catOr if you use the fish shell:
function faketty unbuffer -p $argv end faketty ls --color=auto | cat
This is a great article on how TTYs work and what Pseudo-TTYs (PTYs) are, it's worth taking a look at if you want to understand how the linux shell works with file descriptors to pass around input, output, and signals. http://www.linusakesson.net/programming/tty/index.php