Scp the Three Newest Files Using Bash

perhaps the simplest solution, but it does not deal with spaces in filenames

scp `ls -t | head -3` user@server:.

using xargs has the advantage of dealing with spaces in file names, but will execute scp three times

ls -t | head -3 | xargs -i scp {} user@server:.

a loop based solution would look like this. We use while read here because the default delimiter for read is the newline character not the space character like the for loop

ls -t | head -3 | while read file ; do scp $file user@server ; done

saddly, the perfect solution, one which executes a single scp command while working nicely with white space, eludes me at the moment.

Write a simple bash script. This one will send the last three files as long as they are a file and not a directory.

#!/bin/bash

DIR=`/bin/pwd`for file in `ls -t ${DIR} | head -3`: do  if [ -f ${file} ];  then    scp ${file} user@host:destinationDirectory  fidone

Try this script to scp latest 3 files from supplied 1st argument path to this script:

#!/bin/bashDIR="$1"for f in $(ls -t `find ${DIR} -maxdepth 1 -type f` | head -3) do    scp ${f} user@host:destinationDirectorydone

find -type f makes sure only files are found in ${DIR} and head -3 takes top 3 files.