Test for non-zero length string in Bash: [ -n "$var" ] or [ "$var" ]
Edit: This is a more complete version that shows more differences between [
(aka test
) and [[
.
The following table shows that whether a variable is quoted or not, whether you use single or double brackets and whether the variable contains only a space are the things that affect whether using a test with or without -n/-z
is suitable for checking a variable.
| 1a 2a 3a 4a 5a 6a | 1b 2b 3b 4b 5b 6b | [ [" [-n [-n" [-z [-z" | [[ [[" [[-n [[-n" [[-z [[-z"-----+------------------------------------+------------------------------------unset| false false true false true true | false false false false true truenull | false false true false true true | false false false false true truespace| false true true true true false| true true true true false falsezero | true true true true false false| true true true true false falsedigit| true true true true false false| true true true true false falsechar | true true true true false false| true true true true false falsehyphn| true true true true false false| true true true true false falsetwo | -err- true -err- true -err- false| true true true true false falsepart | -err- true -err- true -err- false| true true true true false falseTstr | true true -err- true -err- false| true true true true false falseFsym | false true -err- true -err- false| true true true true false falseT= | true true -err- true -err- false| true true true true false falseF= | false true -err- true -err- false| true true true true false falseT!= | true true -err- true -err- false| true true true true false falseF!= | false true -err- true -err- false| true true true true false falseTeq | true true -err- true -err- false| true true true true false falseFeq | false true -err- true -err- false| true true true true false falseTne | true true -err- true -err- false| true true true true false falseFne | false true -err- true -err- false| true true true true false false
If you want to know if a variable is non-zero length, do any of the following:
- quote the variable in single brackets (column 2a)
- use
-n
and quote the variable in single brackets (column 4a) - use double brackets with or without quoting and with or without
-n
(columns 1b - 4b)
Notice in column 1a starting at the row labeled "two" that the result indicates that [
is evaluating the contents of the variable as if they were part of the conditional expression (the result matches the assertion implied by the "T" or "F" in the description column). When [[
is used (column 1b), the variable content is seen as a string and not evaluated.
The errors in columns 3a and 5a are caused by the fact that the variable value includes a space and the variable is unquoted. Again, as shown in columns 3b and 5b, [[
evaluates the variable's contents as a string.
Correspondingly, for tests for zero-length strings, columns 6a, 5b and 6b show the correct ways to do that. Also note that any of these tests can be negated if negating shows a clearer intent than using the opposite operation. For example: if ! [[ -n $var ]]
.
If you're using [
, the key to making sure that you don't get unexpected results is quoting the variable. Using [[
, it doesn't matter.
The error messages, which are being suppressed, are "unary operator expected" or "binary operator expected".
This is the script that produced the table above.
#!/bin/bash# by Dennis Williamson# 2010-10-06, revised 2010-11-10# for http://stackoverflow.com/q/3869072# designed to fit an 80 character terminaldw=5 # description column widthw=6 # table column widtht () { printf '%-*s' "$w" " true"; }f () { [[ $? == 1 ]] && printf '%-*s' "$w" " false" || printf '%-*s' "$w" " -err-"; }o=/dev/nullecho ' | 1a 2a 3a 4a 5a 6a | 1b 2b 3b 4b 5b 6b'echo ' | [ [" [-n [-n" [-z [-z" | [[ [[" [[-n [[-n" [[-z [[-z"'echo '-----+------------------------------------+------------------------------------'while read -r d tdo printf '%-*s|' "$dw" "$d" case $d in unset) unset t ;; space) t=' ' ;; esac [ $t ] 2>$o && t || f [ "$t" ] && t || f [ -n $t ] 2>$o && t || f [ -n "$t" ] && t || f [ -z $t ] 2>$o && t || f [ -z "$t" ] && t || f echo -n "|" [[ $t ]] && t || f [[ "$t" ]] && t || f [[ -n $t ]] && t || f [[ -n "$t" ]] && t || f [[ -z $t ]] && t || f [[ -z "$t" ]] && t || f echodone <<'EOF'unsetnullspacezero 0digit 1char chyphn -ztwo a bpart a -aTstr -n aFsym -h .T= 1 = 1F= 1 = 2T!= 1 != 2F!= 1 != 1Teq 1 -eq 1Feq 1 -eq 2Tne 1 -ne 2Fne 1 -ne 1EOF
It is better to use the more powerful [[
as far as Bash is concerned.
Usual cases
if [[ $var ]]; then # var is set and it is not emptyif [[ ! $var ]]; then # var is not set or it is set to an empty string
The above two constructs look clean and readable. They should suffice in most cases.
Note that we don't need to quote the variable expansions inside [[
as there is no danger of word splitting and globbing.
To prevent shellcheck's soft complaints about [[ $var ]]
and [[ ! $var ]]
, we could use the -n
option.
Rare cases
In the rare case of us having to make a distinction between "being set to an empty string" vs "not being set at all", we could use these:
if [[ ${var+x} ]]; then # var is set but it could be emptyif [[ ! ${var+x} ]]; then # var is not setif [[ ${var+x} && ! $var ]]; then # var is set and is empty
We can also use the -v
test:
if [[ -v var ]]; then # var is set but it could be emptyif [[ ! -v var ]]; then # var is not setif [[ -v var && ! $var ]]; then # var is set and is emptyif [[ -v var && -z $var ]]; then # var is set and is empty
Related posts and documentation
There are a plenty of posts related to this topic. Here are a few:
- How to check if a variable is set in Bash?
- How to check if an environment variable exists and get its value?
- How to find whether or not a variable is empty in Bash
- What does “plus colon” (“+:”) mean in shell script expressions?
- Is double square brackets [[ ]] preferable over single square brackets [ ] in Bash?
- What is the difference between single and double square brackets in Bash?
- An excellent answer by mklement0 where he talks about
[[
vs[
- Bash Hackers Wiki -
[
vs[[
Here are some more tests
True if string is not empty:
[ -n "$var" ][[ -n $var ]]test -n "$var"[ "$var" ][[ $var ]](( ${#var} ))let ${#var}test "$var"
True if string is empty:
[ -z "$var" ][[ -z $var ]]test -z "$var"! [ "$var" ]! [[ $var ]]! (( ${#var} ))! let ${#var}! test "$var"