How to print variable addresses in C?
You want to use %p to print a pointer. From the spec:
pThe argument shall be a pointer tovoid. The value of the pointer is converted to a sequence of printing characters, in an implementation-defined manner.
And don't forget the cast, e.g.
printf("%p\n",(void*)&a);
When you intend to print the memory address of any variable or a pointer, using %d won't do the job and will cause some compilation errors, because you're trying to print out a number instead of an address, and even if it does work, you'd have an intent error, because a memory address is not a number. the value 0xbfc0d878 is surely not a number, but an address.
What you should use is %p. e.g.,
#include<stdio.h>int main(void) { int a; a = 5; printf("The memory address of a is: %p\n", (void*) &a); return 0;}Good luck!
To print the address of a variable, you need to use the %p format. %d is for signed integers. For example:
#include<stdio.h>void main(void){ int a; printf("Address is %p:",&a);}