Get only HTML <head> Element with a Script or Tool
It is not possible to load only the data between the <head> tags because the server would have to parse the requested page before sending it.
A possible solution would read a few bytes until a </head> tag is found.
The following reads n bytes from the source and checks if the string </head> is included. If so, the bytes are converted to string and trimmed such that the result contains the tags <head> and </head> as well as the data between them. Otherwise it continues to read n bytes until </head> is found.
import urllib.requestdef get_head_tag_data(url, n=512): """Read n bytes form source until '</head> is included. Trim result to '<head> ... </head>' and return it as string.""" # open resource with urllib.request.urlopen(url) as site: # read n bytes until `buff` includes "</head>" data = b'' i = 1 while True: buff = site.read(n) data += buff if b'</head>' in buff: break elif buff == b'': raise AttributeError('Not head-tag found.') i += 1 print('{} bytes read'.format(n*i)) # cast to string data = str(data) # detect tag position start_tag = data.find('<head>') end_tag = data.find('</head>') + 7 return data[start_tag:end_tag]tag_data = get_head_tag_data('https://stackoverflow.com', n=256)Note that this functions does not check for possible erros, for example if there is no </head> tag.
You can try BeautifulSoap. Here is an example Python script.
import urllib.request as urllib2from bs4 import BeautifulSoup as bsurl = 'change_wiht_your_desired_url' # www.https://stackoverflow.com/questions/48262523/get-only-html-head-element-with-a-script-or-tool page = urllib2.urlopen(url)soup = bs(page, 'html.parser')soup.headYou can get different tags using the soup object. Read the full docs here. I hope this helps.
EDIT
print(soup.head) outputs
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