How to get Link Headers (for pagination) from API using PHP cURL
Ok I got there - In order to preserve the URLs in the headers, contained within angle brackets, I needed to URL encode the output from curl_exec:
$rest = rawurlencode(curl_exec($ch));Example output:
Link%3A%20%3Chttps%3A%2F%2Fapi.mendeley.com%2Fdatasets%3Fmarker%3Db6ea8b2a-c4fa-4a84-989a-66cf7801abbf%26limit%3D3%26sort%3Dpublish_date%26fields%3Dresults.id%26reverse%3Dfalse%26order%3Ddesc
having code like this:
$content = <<<HTMLLink: <meta.rdf>; rel=metaContent.HTML;print_r($content);shows in browser exactly:
Link: ; rel=meta Content.because things within angle brackets are considered to be tags and are not rendered. If you use "crtl+u" shortcut to view sourcecode, you will see:
Link: <meta.rdf>; rel=metaContent.And this means that everything is working fine, and you have everything you need.
I bet that it's your case.