Dart Future.wait for multiple futures and get back results of different types

You need to adapt each of your Future<T>s to a common type of Future. You could use Future<void>:

List<Foo> foos;List<Bar> bars;List<FooBars> foobars;await Future.wait<void>([  downloader.getFoos().then((result) => foos = result),  downloader.getBars().then((result) => bars = result),  downloader.getFooBars().then((result) => foobars = result),]);processData(foos, bars, foobars);

Or if you prefer await to .then(), the Future.wait call could be:

await Future.wait<void>([  (() async => foos = await downloader.getFoos())(),  (() async => bars = await downloader.getBars())(),  (() async => foobars = await downloader.getFooBars())(),]);

I think is not possible to do in a super nice fashion. All you can do is something like this:

void main() async {  List<List<dynamic>> result = await Future.wait<List<dynamic>>([    getStringData(),    getIntData(),  ]);  print(result[0]);  print(result[1]);}Future<List<String>> getStringData() {  return Future.value(["a", "b"]);}Future<List<int>> getIntData() {  return Future.value([1, 2]);}

Well, type T is a generic type

You know your types, so you can work with them.

If your are using a FutureBuilder, you can access the different results using this. (same order you put them in the Future.wait method)

snapshot.data[0] // maybe type List<Foo>snapshot.data[1] // maybe type List<Bar>snapshot.data[2] // maybe type String