IN vs ANY operator in PostgreSQL IN vs ANY operator in PostgreSQL database database

IN vs ANY operator in PostgreSQL


(Neither IN nor ANY is an "operator". A "construct" or "syntax element".)

Logically, quoting the manual:

IN is equivalent to = ANY.

But there are two syntax variants of IN and two variants of ANY. Details:

IN taking a set is equivalent to = ANY taking a set, as demonstrated here:

But the second variant of each is not equivalent to the other. The second variant of the ANY construct takes an array (must be an actual array type), while the second variant of IN takes a comma-separated list of values. This leads to different restrictions in passing values and can also lead to different query plans in special cases:

ANY is more versatile

The ANY construct is far more versatile, as it can be combined with various operators, not just =. Example:

SELECT 'foo' LIKE ANY('{FOO,bar,%oo%}');

For a big number of values, providing a set scales better for each:

Related:

Inversion / opposite / exclusion

"Find rows where id is in the given array":

SELECT * FROM tbl WHERE id = ANY (ARRAY[1, 2]);

Inversion: "Find rows where id is not in the array":

SELECT * FROM tbl WHERE id <> ALL (ARRAY[1, 2]);SELECT * FROM tbl WHERE id <> ALL ('{1, 2}');  -- equivalent array literalSELECT * FROM tbl WHERE NOT (id = ANY ('{1, 2}'));

All three equivalent. The first with array constructor, the other two with array literal. The data type can be derived from context unambiguously. Else, an explicit cast may be required, like '{1,2}'::int[].

Rows with id IS NULL do not pass either of these expressions. To include NULL values additionally:

SELECT * FROM tbl WHERE (id = ANY ('{1, 2}')) IS NOT TRUE;


There are two obvious points, as well as the points in the other answer:

  • They are exactly equivalent when using sub queries:

    SELECT * FROM tableWHERE column IN(subquery);SELECT * FROM tableWHERE column = ANY(subquery);

On the other hand:

  • Only the IN operator allows a simple list:

    SELECT * FROM tableWHERE column IN(… , … , …);

Presuming they are exactly the same has caught me out several times when forgetting that ANY doesn’t work with lists.