Django: field's default value from self model's instances Django: field's default value from self model's instances django django

Django: field's default value from self model's instances


In your examples, you need to remove the call operator ().

Currently the statement is executed immediately at the first read-parsing cycle. By specifying the symbol name instead, the Django class receives a function pointer which it will execute when it actually needs the default value.

The example becomes:

def get_previous():    return ModelA.objects.all()[0].fieldAclass ModelA(models.Model):    fieldA = models.CharField(default=get_previous)

If you're going to do this for a lot of fields, consider overridding the save function, so you only have to fetch the previous object from the database just once.


If you want to just output default value, override __getattr__() method like this:

class ModelA(models.Model):  # your fields  def __getattr__(self, name):    if(name == 'fieldA' and !self.fieldA):      return self.get_previous()    else:      return super(ModelA, self).__getattr__(name)

Saving default value from object will be little difficultier. First solution that comes in my mind, override save() method (i believe there is simpler solution)


Option 1: Use model forms. These are forms based on models, that you can easily populate their values with values from a specific instance. This option is good if you want the default value as something to be shown to the user in forms, obviously.

Option 2: Override the model's save method, and code the check there - if fieldA is None, then put some value in it. This option is better if you want the default value to work at the data layer, and not only as form default values (ie, also for instances you create in other ways).