Django GROUP BY field value

There is not a specific Django ORM way (as far as I know) but you can do the following to get a dictionary of entries grouped by values of a field:

1. Use .values_list() with flat=True to get a list of the existent values in your database (if you don't know them beforehand). Also use .distinct() to elimintae duplicate values as we do not care for those:

   value_list = MyModel.objects.values_list(    'interesting_field', flat=True).distinct()

2. Now iterate through value_list and fill your dictionary:

   group_by_value = {}for value in value_list:    group_by_value[value] = MyModel.objects.filter(interesting_field=value)

Now group_by_value dictionary contains as keys the distinct values in your interesting_field and as values the queryset objects, each containing the entries of MyModel with interesting_field=a value from value_list.

Leaving this here for comment legacy reasons.

I have made a Q&A style example in, which simulates a COUNT ... GROUP BY SQL query.

Essentially you need to utilize the .order_by for grouping and the .annotate() to count on the model's .values().

Here is the above-mentioned example:

We can perform a COUNT ... GROUP BY SQL equivalent query on Django ORM, with the use of annotate(), values(), order_by() and the django.db.models's Count methods:

Let our model be:

class Books(models.Model):    title  = models.CharField()    author = models.CharField()

Lets assume that we want to count how many book objects per distinct author exist in our Book table:

result = Books.objects.values('author')                      .order_by('author')                      .annotate(count=Count('author'))

Now result contains a queryset with two columns: author and count:

  author    | count------------|-------   OneAuthor  |   5 OtherAuthor |   2       ...      |  ...