Django MySQL distinct query for getting multiple values Django MySQL distinct query for getting multiple values django django

Django MySQL distinct query for getting multiple values


.distinct([*fields]) only works in PostgresSQL.

From distinct documentation

Here's the difference. For a normal distinct() call, the database compares each field in each row when determining which rows are distinct. For a distinct() call with specified field names, the database will only compare the specified field names.

As stated all fields in a record are checked. Mostly likely in your case you are getting records with different field values (more likely a case if you are queries multiple tables ManyToMany or ForeignKey relations).

For consolidating as array you can refer your earlier question Django Query distinct values works but i cant use the query result


names = Staff.objects.order_by('person__full_name').values('person__full_name').distinct()

will give you distinct full names, and you can do a similar thing to get distinct job categories.

These will give you lists of values, not objects themselves, but if I interpret your question correctly then I think these will give you what you want.


Not all database support Distinct('field name'). So what we can do is use very simple problem solving skill

 class vendor_ready_distinct(APIView):        def get(self, request):            obj_readyproduct = vendor_list_readyProduct.objects.all().order_by('mobile_number')            unique_list = []            list = []            for x in obj_readyproduct:                # check if exists in unique_list or not                if x.mobile_number not in list:                    unique_list.append(x)                    list.append(x.mobile_number)                seri_obj = vendor_list_readyProductSerializer(unique_list, many=True)            return Response(seri_obj.data)

here we are getting the distinct row by using method 1 from geeksforgeeks