Django upload file into specific directory that depends on the POST URI
Fixed olooney example. It is working now
@csrf_exemptdef upload_video_file(request): folder = 'tmp_dir2/' #request.path.replace("/", "_") uploaded_filename = request.FILES['file'].name BASE_PATH = '/home/' # create the folder if it doesn't exist. try: os.mkdir(os.path.join(BASE_PATH, folder)) except: pass # save the uploaded file inside that folder. full_filename = os.path.join(BASE_PATH, folder, uploaded_filename) fout = open(full_filename, 'wb+') file_content = ContentFile( request.FILES['file'].read() ) try: # Iterate through the chunks. for chunk in file_content.chunks(): fout.write(chunk) fout.close() html = "<html><body>SAVED</body></html>" return HttpResponse(html) except: html = "<html><body>NOT SAVED</body></html>" return HttpResponse(html)
Django gives you total control over where (and if) you save files. See: http://docs.djangoproject.com/en/dev/topics/http/file-uploads/
The below example shows how to combine the URL and the name of the uploaded file and write the file out to disk:
def upload(request): folder = request.path.replace("/", "_") uploaded_filename = request.FILES['file'].name # create the folder if it doesn't exist. try: os.mkdir(os.path.join(BASE_PATH, folder)) except: pass # save the uploaded file inside that folder. full_filename = os.path.join(BASE_PATH, folder, uploaded_filename) fout = open(full_filename, 'wb+') # Iterate through the chunks. for chunk in fout.chunks(): fout.write(chunk) fout.close()Edit: How to do this with a FileUploadHandler? It traced down through the code and it seems like you need to do four things to repurpose the TemporaryFileUploadHandler to save outside of FILE_UPLOAD_TEMP_DIR:
extend TemporaryUploadedFile and override init() to pass through a different directory to NamedTemporaryFile. It can use the try mkdir except for pass I showed above.
extend TemporaryFileUploadHandler and override new_file() to use the above class.
also extend init() to accept the directory where you want the folder to go.
Dynamically add the request handler, passing through a directory determined from the URL:
request.upload_handlers = [ProgressBarUploadHandler(request.path.replace('/', '_')]
While non-trivial, it's still easier than writing a handler from scratch: In particular, you won't have to write a single line of error-prone buffered reading. Steps 3 and 4 are necessary because FileUploadHandlers are not passed request information by default, I believe, so you'll have to tell it separately if you want to use the URL somehow.
I can't really recommend writing a custom FileUploadHandler for this. It's really mixing layers of responsibility. Relative to the speed of uploading a file over the internet, doing a local file copy is insignificant. And if the file's small, Django will just keep it in memory without writing it out to a temp file. I have a bad feeling that you'll get all this working and find you can't even measure the performance difference.