Send Custom message in Django PermissionDenied
This answer is probably arriving very late for you. But here it is.You can use this in your Django code:
raise PermissionDenied("Custom message")And then display the custom message using below snippet in the 403.html template:
{% if exception %} <p>{{ exception }}</p>{% else %} <p>Static generic message</p>{% endif %}The message string passed to 'PermissionDenied' is available in template context as explained in Django documentation - https://docs.djangoproject.com/en/1.10/ref/views/#http-forbidden-view
You can try like this:
class SomeException(Exception): message = 'An error occurred.' def __init__(self, message): self.message = message def __str__(self): return repr(self.message)#usage raise SomeException("Hello, you have an exception here")Another way of sending a message to template is like:
if not request.user.is_staff: #or your condition context['flash_message']= "permission error occurred" retrun render_to_response('template.html', context)# template<!-- I am using bootstrap here --><div class="alert alert-{{ flash_message_type }} flash_message hide"> {{ flash_message | safe }}</div><script>...if($.trim($(".flash_message").html()) != ''){ $(".flash_message").slideDown(); setTimeout(function(){ $(".flash_message").slideUp(); }, 5000); };</script>
I came across the same issue and resolved it using the Django messages framework to pass a custom message to the template.
https://docs.djangoproject.com/en/1.8/ref/contrib/messages/
My specific example:
from django.contrib import messages...messages.error(request, 'The submission deadline has passed.')raise PermissionDeniedThe messages can then be output in the template as described in the documentation.