Python string to two dimensionals list [duplicate]
Your expected output is a list of tuples which you can get with zip, str.split and using iter which is more efficient than slicing.
FuntionStr='AccName,S,Balance,N,AccrInterest,N'it = iter(FuntionStr.split(","))print(list(zip(it,it)))[('AccName', 'S'), ('Balance', 'N'), ('AccrInterest', 'N')]If you have an uneven length list after splitting and you don't want to lose any data you can use zip_longest:
FuntionStr='AccName,S,Balance,N,AccrInterest,N,foo'it = iter(FuntionStr.split(","))from itertools import zip_longestprint(list(zip_longest(it, it,fillvalue="")))]('AccName', 'S'), ('Balance', 'N'), ('AccrInterest', 'N'), ('foo', '')]