Git resolve conflict using --ours/--theirs for all files

Just grep through the working directory and send the output through the xargs command:

grep -lr '<<<<<<<' . | xargs git checkout --ours

or

grep -lr '<<<<<<<' . | xargs git checkout --theirs

How this works: grep will search through every file in the current directory (the .) and subdirectories recursively (the -r flag) looking for conflict markers (the string '<<<<<<<')

the -l or --files-with-matches flag causes grep to output only the filename where the string was found. Scanning stops after first match, so each matched file is only output once.

The matched file names are then piped to xargs, a utility that breaks up the piped input stream into individual arguments for git checkout --ours or --theirs

More at this link.

Since it would be very inconvenient to have to type this every time at the command line, if you do find yourself using it a lot, it might not be a bad idea to create an alias for your shell of choice: Bash is the usual one.

This method should work through at least Git versions 2.4.x

You can -Xours or -Xtheirs with git merge as well. So:

1. abort the current merge (for instance with git reset --hard HEAD)
2. merge using the strategy you prefer (git merge -Xours or git merge -Xtheirs)

DISCLAIMER: of course you can choose only one option, either -Xours or -Xtheirs, do use different strategy you should of course go file by file.

I do not know if there is a way for checkout, but I do not honestly think it is terribly useful: selecting the strategy with the checkout command is useful if you want different solutions for different files, otherwise just go for the merge strategy approach.

git checkout --[ours/theirs] . will do what you want, as long as you're at the root of all conflicts. ours/theirs only affects unmerged files so you shouldn't have to grep/find/etc conflicts specifically.