continue ALLWAYS Illegal in switch in JS but break works fine

continue has absolutely nothing to do with switches, not in Javascript and not in C++:

int main(){    int x = 5, y = 0;    switch (x) {        case 1:            continue;        case 2:            break;        default:            y = 4;    }}

error: continue statement not within a loop

If you wish to break out of the case, use break; otherwise, allow the case to fall through:

switch ("B"){    case "A":        break;    case "B":    case "C":        break;    default:        break;}

If you're looking for a shortcut to jump to the next case then, no, you can't do this.

switch ("B"){    case "A":        break;    case "B":        if (something) {           continue; // nope, sorry, can't do this; use an else        }        // lots of code    case "C":        break;    default:        break;}

I believe you can emulate what you want by using a labeled infinite loop:

var a = "B";loop: while( true ) {    switch (a)    {    case "A":        break loop;    case "B":        a = "C";        continue loop;    case "C":        break loop;    default:        break loop;    }}

Otherwise you should consider expressing what you want in some other way.

Even if you can pull this off, it would be a huge WTF. Just use if else if.

I think what you meant is:

switch ("B"){    case "A":        break;    case "B":    case "C":        break;    default:        break;}

There is no need for continue. When B comes, it will move on to C.