Draw a line with UIBezierPath

Ended up doing it this way:

func drawLineFromPoint(start : CGPoint, toPoint end:CGPoint, ofColor lineColor: UIColor, inView view:UIView) {        //design the path    let path = UIBezierPath()    path.move(to: start)    path.addLine(to: end)        //design path in layer    let shapeLayer = CAShapeLayer()    shapeLayer.path = path.cgPath    shapeLayer.strokeColor = lineColor.CGColor    shapeLayer.lineWidth = 1.0        view.layer.addSublayer(shapeLayer)}

Swift 3.1 Version of William Falcon's Answer + Improved

This is just an updated version of already accepted answer, and I just added a little bit more to it.

func drawLineFromPointToPoint(startX: Int, toEndingX endX: Int, startingY startY: Int, toEndingY endY: Int, ofColor lineColor: UIColor, widthOfLine lineWidth: CGFloat, inView view: UIView) {    let path = UIBezierPath()    path.move(to: CGPoint(x: startX, y: startY))    path.addLine(to: CGPoint(x: endX, y: endY))    let shapeLayer = CAShapeLayer()    shapeLayer.path = path.cgPath    shapeLayer.strokeColor = lineColor.cgColor    shapeLayer.lineWidth = lineWidth    view.layer.addSublayer(shapeLayer)}

And of course the implementation would be

drawLineFromPointToPoint(startX: Int, toEndingX: Int, startingY: Int, toEndingY: Int, ofColor: UIColor, widthOfLine: CGFloat, inView: UIView)

What I changed from accepted answer

I changed the vars to lets, and made it easier to input the start and end of both the x and the y. I also allow the user to change the width of the line.

I chose for the values to be of type Int, but you can change those to be the other allowed options.

Swift 4

func drawLineFromPoint(start : CGPoint, toPoint end:CGPoint, ofColor lineColor: UIColor, inView view:UIView) {    //design the path    let path = UIBezierPath()    path.move(to: start)    path.addLine(to: end)    //design path in layer    let shapeLayer = CAShapeLayer()    shapeLayer.path = path.cgPath    shapeLayer.strokeColor = lineColor.cgColor    shapeLayer.lineWidth = 1.0    view.layer.addSublayer(shapeLayer)}