Get to UIViewController from UIView?

Using the example posted by Brock, I modified it so that it is a category of UIView instead UIViewController and made it recursive so that any subview can (hopefully) find the parent UIViewController.

@interface UIView (FindUIViewController)- (UIViewController *) firstAvailableUIViewController;@end@implementation UIView (FindUIViewController)- (UIViewController *) firstAvailableUIViewController {    UIResponder *responder = [self nextResponder];    while (responder != nil) {        if ([responder isKindOfClass:[UIViewController class]]) {            return (UIViewController *)responder;        }        responder = [responder nextResponder];    }    return nil;}@end

To use this code, add it into an new class file (I named mine "UIKitCategories") and remove the class data... copy the @interface into the header, and the @implementation into the .m file. Then in your project, #import "UIKitCategories.h" and use within the UIView code:

// from a UIView subclass... returns nil if UIViewController not availableUIViewController * myController = [self firstAvailableUIViewController];

UIView is a subclass of UIResponder. UIResponder lays out the method -nextResponder with an implementation that returns nil. UIView overrides this method, as documented in UIResponder (for some reason instead of in UIView) as follows: if the view has a view controller, it is returned by -nextResponder. If there is no view controller, the method will return the superview.

Add this to your project and you're ready to roll.

@interface UIView (APIFix)- (UIViewController *)viewController;@end@implementation UIView (APIFix)- (UIViewController *)viewController {    if ([self.nextResponder isKindOfClass:UIViewController.class])        return (UIViewController *)self.nextResponder;    else        return nil;}@end

Now UIView has a working method for returning the view controller.

Since this has been the accepted answer for a long time, I feel I need to rectify it with a better answer.

Some comments on the need:

• Your view should not need to access the view controller directly.
• The view should instead be independent of the view controller, and be able to work in different contexts.
• Should you need the view to interface in a way with the view controller, the recommended way, and what Apple does across Cocoa is to use the delegate pattern.

An example of how to implement it follows:

@protocol MyViewDelegate < NSObject >- (void)viewActionHappened;@end@interface MyView : UIView@property (nonatomic, assign) MyViewDelegate delegate;@end@interface MyViewController < MyViewDelegate >@end

The view interfaces with its delegate (as UITableView does, for instance) and it doesn't care if its implemented in the view controller or in any other class that you end up using.

My original answer follows: I don't recommend this, neither the rest of the answers where direct access to the view controller is achieved

There is no built-in way to do it. While you can get around it by adding a IBOutlet on the UIView and connecting these in Interface Builder, this is not recommended. The view should not know about the view controller. Instead, you should do as @Phil M suggests and create a protocol to be used as the delegate.