How to change the color of a UIBezierPath in Swift?

With Swift 5, UIColor has a setStroke() method. setStroke() has the following declaration:

func setStroke()

Sets the color of subsequent stroke operations to the color that the receiver represents.

Therefore, you can use setStroke() like this:

strokeColor.setStroke() // where strokeColor is a `UIColor` instance

The Playground code below shows how to use setStroke() alongside UIBezierPath in order to draw a circle with a green fill color and a light grey stroke color inside a UIView subclass:

import UIKitimport PlaygroundSupportclass MyView: UIView {    override func draw(_ rect: CGRect) {        // UIBezierPath        let newRect = CGRect(            x: bounds.minX + ((bounds.width - 79) * 0.5 + 0.5).rounded(.down),            y: bounds.minY + ((bounds.height - 79) * 0.5 + 0.5).rounded(.down),            width: 79,            height: 79        )        let ovalPath = UIBezierPath(ovalIn: newRect)        // Fill        UIColor.green.setFill()        ovalPath.fill()        // Stroke        UIColor.lightGray.setStroke()        ovalPath.lineWidth = 5        ovalPath.stroke()    }}let myView = MyView(frame: CGRect(x: 0, y: 0, width: 200, height: 300))PlaygroundPage.current.liveView = myView

Let's assume you want to use the color red instead to stroke a rounded rectangle;This is how you do it in Swift 3 :

    // Drawing the border of the rounded rectangle:    let redColor = UIColor.red    redColor.setStroke() // Stroke subsequent views with a red color    let roundedRectagle = CGRect(x: 0,y: 0, width: 90,height: 20)    let rectangleBorderPath = UIBezierPath(roundedRect: roundedRectangle,cornerRadius: 5)    roundedRectangle.borderWidth = 1    roundedRectangle.stroke() // Apply the red color stroke on this view

The second and last lines of the above code are important in answering your question.I hope this answer is helpful.