How to implement a regex for password validation in Swift?

You can use Regex for check your password strength

^(?=.*[A-Z].*[A-Z])(?=.*[!@#$&*])(?=.*[0-9].*[0-9])(?=.*[a-z].*[a-z].*[a-z]).{8}$

Regex Explanation : -

^                         Start anchor(?=.*[A-Z].*[A-Z])        Ensure string has two uppercase letters.(?=.*[!@#$&*])            Ensure string has one special case letter.(?=.*[0-9].*[0-9])        Ensure string has two digits.(?=.*[a-z].*[a-z].*[a-z]) Ensure string has three lowercase letters..{8}                      Ensure string is of length 8.$                         End anchor.

Source - Rublar Link

try with this one for Password must be more than 6 characters, with at least one capital, numeric or special character

^.*(?=.{6,})(?=.*[A-Z])(?=.*[a-zA-Z])(?=.*\\d)|(?=.*[!#$%&? "]).*$

^ assert position at start of the string.* matches any character (except newline)Quantifier: * Between zero and unlimited times, as many times as possible, giving back as needed [greedy](?=.{6,}) Positive Lookahead - Assert that the regex below can be matched.{6,} matches any character (except newline)Quantifier: {6,} Between 6 and unlimited times, as many times as possible, giving back as needed [greedy](?=.*[A-Z]) Positive Lookahead - Assert that the regex below can be matched.* matches any character (except newline)Quantifier: * Between zero and unlimited times, as many times as possible, giving back as needed [greedy][A-Z] match a single character present in the list belowA-Z a single character in the range between A and Z (case sensitive)(?=.*[a-zA-Z]) Positive Lookahead - Assert that the regex below can be matched.* matches any character (except newline)Quantifier: * Between zero and unlimited times, as many times as possible, giving back as needed [greedy][a-zA-Z] match a single character present in the list belowa-z a single character in the range between a and z (case sensitive)A-Z a single character in the range between A and Z (case sensitive)(?=.*\\d) Positive Lookahead - Assert that the regex below can be matched.* matches any character (except newline)Quantifier: * Between zero and unlimited times, as many times as possible, giving back as needed [greedy]\d match a digit [0-9]2nd Alternative: (?=.*[!#$%&? "]).*$(?=.*[!#$%&? "]) Positive Lookahead - Assert that the regex below can be matched.* matches any character (except newline)Quantifier: * Between zero and unlimited times, as many times as possible, giving back as needed [greedy][!#$%&? "] match a single character present in the list below!#$%&? " a single character in the list !#$%&? " literally (case sensitive).* matches any character (except newline)Quantifier: * Between zero and unlimited times, as many times as possible, giving back as needed [greedy]$ assert position at end of the string

https://regex101.com/#javascript

more this you can try ....

Minimum 8 characters at least 1 Alphabet and 1 Number:

"^(?=.*[A-Za-z])(?=.*\\d)[A-Za-z\\d]{8,}$"

Minimum 8 characters at least 1 Alphabet, 1 Number and 1 Special Character:

"^(?=.*[A-Za-z])(?=.*\\d)(?=.*[$@$!%*#?&])[A-Za-z\\d$@$!%*#?&]{8,}$"

Minimum 8 characters at least 1 Uppercase Alphabet, 1 Lowercase Alphabet and 1 Number:

"^(?=.*[a-z])(?=.*[A-Z])(?=.*\\d)[a-zA-Z\\d]{8,}$"

Minimum 8 characters at least 1 Uppercase Alphabet, 1 Lowercase Alphabet, 1 Number and 1 Special Character:

"^(?=.*[a-z])(?=.*[A-Z])(?=.*\\d)(?=.*[d$@$!%*?&#])[A-Za-z\\dd$@$!%*?&#]{8,}"

Minimum 8 and Maximum 10 characters at least 1 Uppercase Alphabet, 1 Lowercase Alphabet, 1 Number and 1 Special Character:

"^(?=.*[a-z])(?=.*[A-Z])(?=.*\\d)(?=.*[$@$!%*?&#])[A-Za-z\\d$@$!%*?&#]{8,10}"

public func isValidPassword() -> Bool {    let passwordRegex = "^(?=.*\\d)(?=.*[a-z])(?=.*[A-Z])[0-9a-zA-Z!@#$%^&*()\\-_=+{}|?>.<,:;~`’]{8,}$"    return NSPredicate(format: "SELF MATCHES %@", passwordRegex).evaluate(with: self)}

If you need a quick fix. This is validation for a password with regex. Copy/paste in helper or extension file and use it.