How to initialize a custom prototype style table cell in iOS 5 storyboards?

This way

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath {    static NSString *CellIdentifier = @"Cell";    CustomCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier];    if (cell == nil) {        cell = [[CustomCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier];    }    return cell;}

This worked perfect for me (Xcode 4.5.2 and iOS 6.0):

-(UITableViewCell *) tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath{    UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:@"Cell"];    if( cell == nil){        cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:@"Cell"];    }    UILabel *title = (UILabel*) [cell viewWithTag:1000];    UILabel *summary = (UILabel*) [cell viewWithTag:1001];    [title setText:[ tableMainTitle objectAtIndex:indexPath.row]];    [summary setText:[ tableSubTitle objectAtIndex:indexPath.row]];    return cell;}

Important: Do not forget setting delegate and datasource.

If you load your view controller that contains the tableview using:

MyViewController *myViewController = [self.storyboard instantiateViewControllerWithIdentifier:@"MyViewController"];

Then inside cellForRowAtIndexPath you just need one line:

UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:@"MyIdentifierFromStoryboard"];

dequeueReusableCellWithIdentifier will instantiate one cell if there is none exists.