Open Settings App from another App in iOS - React Native
You can access settings of the application with:Linking.openURL('app-settings:');
But I don't know (yet) how to open a specific deep-link.
2021 update use:
Linking.openSettings();
otherwise your app will be rejected due use of non-public URL scheme
I successfully opened the settings by the code below, hope it's helpful :)
Linking.canOpenURL('app-settings:').then(supported => { if (!supported) { console.log('Can\'t handle settings url'); } else { return Linking.openURL('app-settings:'); }}).catch(err => console.error('An error occurred', err));Reference: https://facebook.github.io/react-native//docs/linking.html
Since React Native version 0.59 this should be possible using openSettings();. This is described in the React Native Linking documentation. Although it did not work for me. When I tried quickly I saw a _reactNative.Linking.openSettings is not a function error message.
Linking.openSettings();