Open Whatsapp on a particular number in swift

Its possible You can send messages to Specfic user.

Direct app chat url open

let urlWhats = "whatsapp://send?phone=+919789384445&abid=12354&text=Hello"    if let urlString = urlWhats.addingPercentEncoding(withAllowedCharacters: NSCharacterSet.urlQueryAllowed) {        if let whatsappURL = URL(string: urlString) {            if UIApplication.shared.canOpenURL(whatsappURL!) {                UIApplication.shared.openURL(whatsappURL!)            } else {                print("Install Whatsapp")            }        }    }

Note:Country code (Ex:+91) is mandatory to open mobile number Chat

WebUrl Link open Chat

 let whatsappURL = URL(string: "https://api.whatsapp.com/send?phone=9512347895&text=Invitation")    if UIApplication.shared.canOpenURL(whatsappURL) {        UIApplication.shared.open(whatsappURL, options: [:], completionHandler: nil)    }

Check below link,

https://www.whatsapp.com/faq/en/general/26000030

Note: Add url scheme in info.plist

<key>LSApplicationQueriesSchemes</key> <array>    <string>whatsapp</string> </array>

For swift 4.2 / Swift 5

func openWhatsapp(){    let urlWhats = "whatsapp://send?phone=(mobile number with country code)"    if let urlString = urlWhats.addingPercentEncoding(withAllowedCharacters: CharacterSet.urlQueryAllowed){        if let whatsappURL = URL(string: urlString) {            if UIApplication.shared.canOpenURL(whatsappURL){                if #available(iOS 10.0, *) {                    UIApplication.shared.open(whatsappURL, options: [:], completionHandler: nil)                } else {                    UIApplication.shared.openURL(whatsappURL)                }            }            else {                print("Install Whatsapp")            }        }    }}

For Swift 2.0

let urlWhats = "whatsapp://send?phone=(mobile number with country code)"        if let urlString = urlWhats.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLQueryAllowedCharacterSet()){            if let whatsappURL = NSURL(string: urlString) {                if UIApplication.sharedApplication().canOpenURL(whatsappURL){                    UIApplication.sharedApplication().openURL(whatsappURL)                }                else {                    print("Install Whatsapp")                }            }        }

Note: Add url scheme in info.plist

<key>LSApplicationQueriesSchemes</key> <array>    <string>whatsapp</string> </array>

This worked neatly for me

    if let url = URL(string: "https://wa.me/91xxxxxxxxxx?text=Hello"),            UIApplication.shared.canOpenURL(url) {                UIApplication.shared.open(url, options: [:])    }