The answer is simply that it makes no difference how the segue is triggered.

The prepareForSegue:sender: method is called in any case and this is where you pass your parameters across.

Old question but here's the code on how to do what you are asking. In this case I am passing data from a selected cell in a table view to another view controller.

in the .h file of the trget view:

@property(weak, nonatomic)  NSObject* dataModel;

in the .m file:

@synthesize dataModel;

dataModel can be string, int, or like in this case it's a model that contains many items

- (void)someMethod {     [self performSegueWithIdentifier:@"loginMainSegue" sender:self]; }

OR...

- (void)someMethod {    UIViewController *myController = [self.storyboard instantiateViewControllerWithIdentifier:@"HomeController"];    [self.navigationController pushViewController: myController animated:YES];}- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender {    if([segue.identifier isEqualToString:@"storyDetailsSegway"]) {        UITableViewCell *cell = (UITableViewCell *) sender;        NSIndexPath *indexPath = [self.tableView indexPathForCell:cell];        NSDictionary *storiesDict =[topStories objectAtIndex:[indexPath row]];        StoryModel *storyModel = [[StoryModel alloc] init];        storyModel = storiesDict;        StoryDetails *controller = (StoryDetails *)segue.destinationViewController;        controller.dataModel= storyModel;    }}

Swift 4:

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {    if segue.identifier == "ExampleSegueIdentifier" {        if let destinationVC = segue.destination as? ExampleSegueVC {            destinationVC.exampleString = "Example"        }    }}

Swift 3:

override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {        if segue.identifier == "ExampleSegueIdentifier" {            if let destinationVC = segue.destinationViewController as? ExampleSegueVC {                destinationVC.exampleString = "Example"            }        }    }