Swift: how to return class type from function

You can return any type you want.

func getTypeOfInt()  -> Int.Type  { return Int.self  }func getTypeOfBool() -> Bool.Type { return Bool.self }

If the type is not determined from arguments or if the return is constant, there is no need to introduce a generic T type.

ios swift generics

It works when I modify your function like this:

func getGeneric<T>(object: T) -> T.Type {    return T.self}getGeneric(0)    // Swift.Int

ios swift generics

You can force the downcast (as!) as below

func getGeneric<T>() -> T.Type {  return Int.self as! T.Type}

But out of the function scope, you need to indicate the returned type:

var t:Int.Type = getGeneric()

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