Swift regex: does a string match a pattern?

Swift version 3 solution:

if string.range(of: regex, options: .regularExpression, range: nil, locale: nil) != nil ...

Swift version 2 solution:

if string.rangeOfString(pattern, options: .RegularExpressionSearch) != nil ...

Example -- does this string contain two letter "o" characters?

"hello world".rangeOfString("o.*o", options: .RegularExpressionSearch) != nil

Note: If you get the error message 'String' does not have a member 'rangeOfString', then add this before: import Foundation. This is because Foundation provides the NSString methods that are automatically bridged to the Swift String class.

import Foundation

Thanks to Onno Eberhard for the Swift 3 update.

The solutions mentioned above didn't work for me anymore, so I'm posting my solution here (I used an extension for String):

extension String {    func matches(_ regex: String) -> Bool {        return self.range(of: regex, options: .regularExpression, range: nil, locale: nil) != nil    }}

Example:

if str.matches("^[a-zA-Z0-9._-]{1,30}$") {    //...}

To get the syntax you actually ask about, you can easily define a new operator which wraps the bridged NSString functionality:

infix operator =~ {}func =~(string:String, regex:String) -> Bool {    return string.rangeOfString(regex, options: .RegularExpressionSearch) != nil}"abcd" =~ "ab*cd""abcd" =~ "abcde+"