@Autowired and static method
You can do this by following one of the solutions:
Using constructor @Autowired
This approach will construct the bean requiring some beans as constructor parameters. Within the constructor code you set the static field with the value got as parameter for constructor execution. Sample:
@Componentpublic class Boo { private static Foo foo; @Autowired public Boo(Foo foo) { Boo.foo = foo; } public static void randomMethod() { foo.doStuff(); }}
Using @PostConstruct to hand value over to static field
The idea here is to hand over a bean to a static field after bean is configured by spring.
@Componentpublic class Boo { private static Foo foo; @Autowired private Foo tFoo; @PostConstruct public void init() { Boo.foo = tFoo; } public static void randomMethod() { foo.doStuff(); }}
You have to workaround this via static application context accessor approach:
@Componentpublic class StaticContextAccessor { private static StaticContextAccessor instance; @Autowired private ApplicationContext applicationContext; @PostConstruct public void registerInstance() { instance = this; } public static <T> T getBean(Class<T> clazz) { return instance.applicationContext.getBean(clazz); }}
Then you can access bean instances in a static manner.
public class Boo { public static void randomMethod() { StaticContextAccessor.getBean(Foo.class).doStuff(); }}
What you can do is @Autowired
a setter method and have it set a new static field.
public class Boo { @Autowired Foo foo; static Foo staticFoo; @Autowired public void setStaticFoo(Foo foo) { Boo.staticFoo = foo; } public static void randomMethod() { staticFoo.doStuff(); }}
When the bean gets processed, Spring will inject a Foo
implementation instance into the instance field foo
. It will then also inject the same Foo
instance into the setStaticFoo()
argument list, which will be used to set the static field.
This is a terrible workaround and will fail if you try to use randomMethod()
before Spring has processed an instance of Boo
.