How can I prevent java.lang.NumberFormatException: For input string: "N/A"? [closed]
"N/A" is not an integer. It must throw NumberFormatException if you try to parse it to an integer.
Check before parsing or handle Exception properly.
Exception Handling
try{ int i = Integer.parseInt(input);} catch(NumberFormatException ex){ // handle your exception ...}
or - Integer pattern matching -
String input=...;String pattern ="-?\\d+";if(input.matches("-?\\d+")){ // any positive or negetive integer or not! ...}
Integer.parseInt(str) throws NumberFormatException if the string does not contain a parsable integer. You can hadle the same as below.
int a;String str = "N/A";try { a = Integer.parseInt(str);} catch (NumberFormatException nfe) { // Handle the condition when str is not a number.}
Make an exception handler like this,
private int ConvertIntoNumeric(String xVal){ try { return Integer.parseInt(xVal); } catch(Exception ex) { return 0; }}....int xTest = ConvertIntoNumeric("N/A"); //Will return 0