How do I set the default Java installation/runtime (Windows)?
This is a bit of a pain on Windows. Here's what I do.
Install latest Sun JDK, e.g. 6u11, in path like c:\install\jdk\sun\6u11
, then let the installer install public JRE in the default place (c:\program files\blah
). This will setup your default JRE for the majority of things.
Install older JDKs as necessary, like 5u18 in c:\install\jdk\sun\5u18
, but don't install the public JREs.
When in development, I have a little batch file that I use to setup a command prompt for each JDK version. Essentially just set JAVA_HOME=c:\jdk\sun\JDK_DESIRED
and then set PATH=%JAVA_HOME%\bin;%PATH%
. This will put the desired JDK first in the path and any secondary tools like Ant or Maven can use the JAVA_HOME
variable.
The path is important because most public JRE installs put a linked executable at c:\WINDOWS\System32\java.exe
, which usually overrides most other settings.
I have patched the behaviour of my eclipse startup shortcut in the properties dialogue
from
"E:\Program Files\eclipse\eclipse.exe"
to
"E:\Program Files\eclipse\eclipse.exe" -vm "E:\Program Files\Java\jdk1.6.0_30\bin"
as described in the Eclipse documentation
It is a patch only, as it depends on the shortcut to fix things...
The alternative is to set the parameter permanently in the eclipse initialisation file.
I just had that problem (Java 1.8 vs. Java 9 on Windows 7) and my findings are:
short version
default seems to be (because of Path entry)
c:\ProgramData\Oracle\Java\javapath\java -version
select the version you want (test, use tab completing in cmd, not sure what those numbers represent), I had 2 options, see longer version for details
c:\ProgramData\Oracle\Java\javapath_target_[tab]
remove junction/link and link to your version (the one ending with 181743567 in my case for Java 8)
rmdir javapathmklink /D javapath javapath_target_181743567
longer version:
Reinstall Java 1.8 after Java 9 didn't work. The sequence of installations was jdk1.8.0_74, jdk-9.0.4 and attempt to make Java 8 default with jdk1.8.0_162...
After jdk1.8.0_162 installation I still have
java -versionjava version "9.0.4"Java(TM) SE Runtime Environment (build 9.0.4+11)Java HotSpot(TM) 64-Bit Server VM (build 9.0.4+11, mixed mode)
What I see in path is
Path=...;C:\ProgramData\Oracle\Java\javapath;...
So I checked what is that and I found it is a junction (link)
c:\ProgramData\Oracle\Java>dir Volume in drive C is OSDisk Volume Serial Number is DA2F-C2CC Directory of c:\ProgramData\Oracle\Java2018-02-07 17:06 <DIR> .2018-02-07 17:06 <DIR> ..2018-02-08 17:08 <DIR> .oracle_jre_usage2017-08-22 11:04 <DIR> installcache2018-02-08 17:08 <DIR> installcache_x642018-02-07 17:06 <JUNCTION> javapath [C:\ProgramData\Oracle\Java\javapath_target_185258831]2018-02-07 17:06 <DIR> javapath_target_1817435672018-02-07 17:06 <DIR> javapath_target_185258831
Those hashes doesn't ring a bell, but when I checked
c:\ProgramData\Oracle\Java\javapath_target_181743567>.\java -versionjava version "1.8.0_162"Java(TM) SE Runtime Environment (build 1.8.0_162-b12)Java HotSpot(TM) 64-Bit Server VM (build 25.162-b12, mixed mode)c:\ProgramData\Oracle\Java\javapath_target_185258831>.\java -versionjava version "9.0.4"Java(TM) SE Runtime Environment (build 9.0.4+11)Java HotSpot(TM) 64-Bit Server VM (build 9.0.4+11, mixed mode)
so to make Java 8 default again I had to delete the link as described here
rmdir javapath
and recreate with Java I wanted
mklink /D javapath javapath_target_181743567
tested:
c:\ProgramData\Oracle\Java>java -versionjava version "1.8.0_162"Java(TM) SE Runtime Environment (build 1.8.0_162-b12)Java HotSpot(TM) 64-Bit Server VM (build 25.162-b12, mixed mode)
** update (Java 10) **
With Java 10 it is similar, only javapath is in c:\Program Files (x86)\Common Files\Oracle\Java\ which is strange as I installed 64-bit IMHO
.\java -versionjava version "10.0.2" 2018-07-17Java(TM) SE Runtime Environment 18.3 (build 10.0.2+13)Java HotSpot(TM) 64-Bit Server VM 18.3 (build 10.0.2+13, mixed mode)