Initialize a long in Java

java long-integer

BTW: it doesn't have to be an upper case L, but lower case is confused with 1 many times :).

java long-integer

You need to add the L character to the end of the number to make Java recognize it as a long.
```
long i = 12345678910L;
```
Yes.

See Primitive Data Types which says "An integer literal is of type long if it ends with the letter L or l; otherwise it is of type int."

java long-integer

You need to add uppercase L at the end like so

long i = 12345678910L;

Same goes true for float with 3.0f

Which should answer both of your questions

CodeHunter