JPA/Criteria API - Like & equal problem
Perhaps you need
criteria.add(cb.like(emp.<String>get("name"), p));because first argument of like() is Expression<String>, not Expression<?> as in equal().
Another approach is to enable generation of the static metamodel (see docs of your JPA implementation) and use typesafe Criteria API:
criteria.add(cb.like(emp.get(Employee_.name), p));(Note that you can't get static metamodel from em.getMetamodel(), you need to generate it by external tools).
Better: predicate (not ParameterExpression), like this :
List<Predicate> predicates = new ArrayList<Predicate>();if(reference!=null){ Predicate condition = builder.like(root.<String>get("reference"),"%"+reference+"%"); predicates.add(condition);}
It will work with a small addition of .as(String.class):
criteria.add(cb.like(emp.get("name").as(String.class), p));