What should I set JAVA_HOME environment variable on macOS X 10.6?

I just set JAVA_HOME to the output of that command, which should give you the Java path specified in your Java preferences. Here's a snippet from my .bashrc file, which sets this variable:

export JAVA_HOME=$(/usr/libexec/java_home)

I haven't experienced any problems with that technique.

Occasionally I do have to change the value of JAVA_HOME to an earlier version of Java. For example, one program I'm maintaining requires 32-bit Java 5 on OS X, so when using that program, I set JAVA_HOME by running:

export JAVA_HOME=$(/usr/libexec/java_home -v 1.5)

For those of you who don't have java_home in your path add it like this.

sudo ln -s /System/Library/Frameworks/JavaVM.framework/Versions/Current/Commands/java_home /usr/libexec/java_home

References:

• Oracle explains the java_home command

• An article for configuring the JDK in Spring Tool Suite (Eclipse2019) on MacOS

Also, it`s interesting to set your PATH to reflect the JDK. After adding JAVA_HOME (which can be done with the example cited by 'mipadi'):

export JAVA_HOME=$(/usr/libexec/java_home)

Add also in ~/.profile:

export PATH=${JAVA_HOME}/bin:$PATH

P.S.: For OSX, I generally use .profile in the HOME dir instead of .bashrc

I am having MAC OS X(Sierra) 10.12.2.

I set JAVA_HOME to work on React Native(for Android apps) by following the following steps.

• Open Terminal (Command+R, type Terminal, Hit ENTER).

• Add the following lines to ~/.bash_profile.export JAVA_HOME=$(/usr/libexec/java_home)

• Now run the following command. source ~/.bash_profile

• You can check the exact value of JAVA_HOME by typing the following command.echo $JAVA_HOME

The value(output) returned will be something like below./Library/Java/JavaVirtualMachines/jdk1.8.0_131.jdk/Contents/Home

That's it.