Expect Arrays to be equal ignoring order
If it's just integers or other primitive values, you can sort() them before comparing.
expect(array1.sort()).toEqual(array2.sort());If its objects, combine it with the map() function to extract an identifier that will be compared
array1 = [{id:1}, {id:2}, {id:3}];array2 = [{id:3}, {id:2}, {id:1}];expect(array1.map(a => a.id).sort()).toEqual(array2.map(a => a.id).sort());
You could use expect.arrayContaining(array) from standard jest:
const expected = ['Alice', 'Bob']; it('matches even if received contains additional elements', () => { expect(['Alice', 'Bob', 'Eve']).toEqual(expect.arrayContaining(expected)); });
jasmine version 2.8 and later has
jasmine.arrayWithExactContents()Which expects that an array contains exactly the elements listed, in any order.
array1 = [1,2,3];array2 = [3,2,1];expect(array1).toEqual(jasmine.arrayWithExactContents(array2))