Fastest method to replace all instances of a character in a string [duplicate]
The easiest would be to use a regular expression with g
flag to replace all instances:
str.replace(/foo/g, "bar")
This will replace all occurrences of foo
with bar
in the string str
. If you just have a string, you can convert it to a RegExp object like this:
var pattern = "foobar", re = new RegExp(pattern, "g");
Try this replaceAll:http://dumpsite.com/forum/index.php?topic=4.msg8#msg8
String.prototype.replaceAll = function(str1, str2, ignore) { return this.replace(new RegExp(str1.replace(/([\/\,\!\\\^\$\{\}\[\]\(\)\.\*\+\?\|\<\>\-\&])/g,"\\$&"),(ignore?"gi":"g")),(typeof(str2)=="string")?str2.replace(/\$/g,"$$$$"):str2);}
It is very fast, and it will work for ALL these conditionsthat many others fail on:
"x".replaceAll("x", "xyz");// xyz"x".replaceAll("", "xyz");// xyzxxyz"aA".replaceAll("a", "b", true);// bb"Hello???".replaceAll("?", "!");// Hello!!!
Let me know if you can break it, or you have something better, but make sure it can pass these 4 tests.
var mystring = 'This is a string';var newString = mystring.replace(/i/g, "a");
newString now is 'Thas as a strang'