How can I extract a number from a string in JavaScript?
For this specific example,
var thenum = thestring.replace( /^\D+/g, ''); // replace all leading non-digits with nothing
in the general case:
thenum = "foo3bar5".match(/\d+/)[0] // "3"
Since this answer gained popularity for some reason, here's a bonus: regex generator.
function getre(str, num) { if(str === num) return 'nice try'; var res = [/^\D+/g,/\D+$/g,/^\D+|\D+$/g,/\D+/g,/\D.*/g, /.*\D/g,/^\D+|\D.*$/g,/.*\D(?=\d)|\D+$/g]; for(var i = 0; i < res.length; i++) if(str.replace(res[i], '') === num) return 'num = str.replace(/' + res[i].source + '/g, "")'; return 'no idea';};function update() { $ = function(x) { return document.getElementById(x) }; var re = getre($('str').value, $('num').value); $('re').innerHTML = 'Numex speaks: <code>' + re + '</code>';}
<p>Hi, I'm Numex, the Number Extractor Oracle.<p>What is your string? <input id="str" value="42abc"></p><p>What number do you want to extract? <input id="num" value="42"></p><p><button onclick="update()">Insert Coin</button></p><p id="re"></p>
You should try the following:
var txt = "#div-name-1234-characteristic:561613213213";var numb = txt.match(/\d/g);numb = numb.join("");alert (numb);
result
1234561613213213
I think this regular expression will serve your purpose:
var num = txt.replace(/[^0-9]/g,'');
Where txt
is your string.
It basically rips off anything that is not a digit.
I think you can achieve the same thing by using this as well :
var num = txt.replace(/\D/g,'');