How to determine the OS path separator in JavaScript? How to determine the OS path separator in JavaScript? javascript javascript

How to determine the OS path separator in JavaScript?


Use path module in node.js returns the platform-specific file separator.
example

path.sep  // on *nix evaluates to a string equal to "/"

Edit: As per Sebas's comment below, to use this, you need to add this at the top of your js file:

const path = require('path')


Afair you can always use / as a path separator, even on Windows.

Quote from http://bytes.com/forum/thread23123.html:

So, the situation can be summed up rather simply:

  • All DOS services since DOS 2.0 and all Windows APIs accept either forward slash or backslash. Always have.

  • None of the standard command shells (CMD or COMMAND) will accept forward slashes. Even the "cd ./tmp" example given in a previous post fails.


The Correct Answer

Yes all OS's accept CD ../ or CD ..\ or CD .. regardless of how you pass in separators. But what about reading a path back. How would you know if its say, a 'windows' path, with ' ' and \ allowed.

The Obvious 'Duh!' Question

What happens when you depend on, for example, the installation directory %PROGRAM_FILES% (x86)\Notepad++. Take the following example.

var fs = require('fs');                             // file system modulevar targetDir = 'C:\Program Files (x86)\Notepad++'; // target installer dir// read all files in the directoryfs.readdir(targetDir, function(err, files) {    if(!err){        for(var i = 0; i < files.length; ++i){            var currFile = files[i];            console.log(currFile);             // ex output: 'C:\Program Files (x86)\Notepad++\notepad++.exe'            // attempt to print the parent directory of currFile            var fileDir = getDir(currFile);            console.log(fileDir);              // output is empty string, ''...what!?        }    }});function getDir(filePath){    if(filePath !== '' && filePath != null){       // this will fail on Windows, and work on Others       return filePath.substring(0, filePath.lastIndexOf('/') + 1);    }}

What happened!?

targetDir is being set to a substring between the indices 0, and 0 (indexOf('/') is -1 in C:\Program Files\Notepad\Notepad++.exe), resulting in the empty string.

The Solution...

This includes code from the following post: How do I determine the current operating system with Node.js

myGlobals = { isWin: false, isOsX:false, isNix:false };

Server side detection of OS.

// this var could likely a global or available to all parts of your appif(/^win/.test(process.platform))     { myGlobals.isWin=true; }else if(process.platform === 'darwin'){ myGlobals.isOsX=true; }else if(process.platform === 'linux') { myGlobals.isNix=true; }

Browser side detection of OS

var appVer = navigator.appVersion;if      (appVer.indexOf("Win")!=-1)   myGlobals.isWin = true;else if (appVer.indexOf("Mac")!=-1)   myGlobals.isOsX = true;else if (appVer.indexOf("X11")!=-1)   myGlobals.isNix = true;else if (appVer.indexOf("Linux")!=-1) myGlobals.isNix = true;

Helper Function to get the separator

function getPathSeparator(){    if(myGlobals.isWin){        return '\\';    }    else if(myGlobals.isOsx  || myGlobals.isNix){        return '/';    }    // default to *nix system.    return '/';}// modifying our getDir method from above...

Helper function to get the parent directory (cross platform)

function getDir(filePath){    if(filePath !== '' && filePath != null){       // this will fail on Windows, and work on Others       return filePath.substring(0, filePath.lastIndexOf(getPathSeparator()) + 1);    }}

getDir() must be intelligent enough to know which its looking for.

You can get even really slick and check for both if the user is inputting a path via command line, etc.

// in the body of getDir() ...var sepIndex = filePath.lastIndexOf('/');if(sepIndex == -1){    sepIndex = filePath.lastIndexOf('\\');}// include the trailing separatorreturn filePath.substring(0, sepIndex+1);

You can also use 'path' module and path.sep as stated above, if you want to load a module to do this simple of a task. Personally, i think it sufficient to just check the information from the process that is already available to you.

var path = require('path');var fileSep = path.sep;    // returns '\\' on windows, '/' on *nix

And Thats All Folks!