How to get file name from content-disposition

Here is how I used it sometime back.I'm assuming you are providing the attachment as a server response.

I set the response header like this from my REST service response.setHeader("Content-Disposition", "attachment;filename=XYZ.csv");

function(response, status, xhr){    var filename = "";    var disposition = xhr.getResponseHeader('Content-Disposition');    if (disposition && disposition.indexOf('attachment') !== -1) {        var filenameRegex = /filename[^;=\n]*=((['"]).*?\2|[^;\n]*)/;        var matches = filenameRegex.exec(disposition);        if (matches != null && matches[1]) {           filename = matches[1].replace(/['"]/g, '');        }    }}

EDIT:Editing the answer to suit your question- use of the word inline instead of attachment

function(response, status, xhr){    var filename = "";    var disposition = xhr.getResponseHeader('Content-Disposition');    if (disposition && disposition.indexOf('inline') !== -1) {        var filenameRegex = /filename[^;=\n]*=((['"]).*?\2|[^;\n]*)/;        var matches = filenameRegex.exec(disposition);        if (matches != null && matches[1]) {           filename = matches[1].replace(/['"]/g, '');        }    }}

More here

This is an improvement on marjon4's answer.

A much simplified way to the selected answer would be to use split like this;

var fileName = xhr.getResponseHeader('content-disposition').split('filename=')[1].split(';')[0];

Note: This solution may not work as expected if your file name itself contains a semi-colon (;)

Or simply just:

var fileName = xhr.getResponseHeader('Content-Disposition').split("filename=")[1];