Is there a “not in” operator in JavaScript for checking object properties?
It seems wrong to me to set up an if/else statement just to use the else portion...
Just negate your condition, and you'll get the else logic inside the if:
if (!(id in tutorTimes)) { ... }
As already said by Jordão, just negate it:
if (!(id in tutorTimes)) { ... }Note: The above test if tutorTimes has a property with the name specified in id, anywhere in the prototype chain. For example "valueOf" in tutorTimes returns true because it is defined in Object.prototype.
If you want to test if a property doesn't exist in the current object, use hasOwnProperty:
if (!tutorTimes.hasOwnProperty(id)) { ... }Or if you might have a key that is hasOwnPropery you can use this:
if (!Object.prototype.hasOwnProperty.call(tutorTimes,id)) { ... }
Personally I find
if (id in tutorTimes === false) { ... }easier to read than
if (!(id in tutorTimes)) { ... }but both will work.