jQuery each loop in table row [duplicate]

In jQuery just use:

$('#tblOne > tbody  > tr').each(function() {...code...});

Using the children selector (>) you will walk over all the children (and not all descendents), example with three rows:

$('table > tbody  > tr').each(function(index, tr) {    console.log(index);   console.log(tr);});

Result:

0<tr>1 <tr>2<tr>

In VanillaJS you can use document.querySelectorAll() and walk over the rows using forEach()

[].forEach.call(document.querySelectorAll('#tblOne > tbody  > tr'), function(index, tr) {    /* console.log(index); */    /* console.log(tr); */});

Just a recommendation:

I'd recommend using the DOM table implementation, it's very straight forward and easy to use, you really don't need jQuery for this task.

var table = document.getElementById('tblOne');var rowLength = table.rows.length;for(var i=0; i<rowLength; i+=1){  var row = table.rows[i];  //your code goes here, looping over every row.  //cells are accessed as easy  var cellLength = row.cells.length;  for(var y=0; y<cellLength; y+=1){    var cell = row.cells[y];    //do something with every cell here  }}

Use immediate children selector >:

$('#tblOne > tbody  > tr')

Description: Selects all direct child elements specified by "child" of elements specified by "parent".