Remove an item from array using UnderscoreJS
Just using plain JavaScript, this has been answered already: remove objects from array by object property.
Using underscore.js, you could combine .findWhere with .without:
var arr = [{ id: 1, name: 'a'}, { id: 2, name: 'b'}, { id: 3, name: 'c'}];//substract thirdarr = _.without(arr, _.findWhere(arr, { id: 3}));console.log(arr);<script src="https://cdnjs.cloudflare.com/ajax/libs/underscore.js/1.8.3/underscore-min.js"></script>Although, since you are creating a new array in this case anyway, you could simply use _.filter or the native Array.prototype.filter function (just like shown in the other question). Then you would only iterate over array once instead of potentially twice like here.
If you want to modify the array in-place, you have to use .splice. This is also shown in the other question and undescore doesn't seem to provide any useful function for that.
You can use Underscore .filter
var arr = [{ id: 1, name: 'a' }, { id: 2, name: 'b' }, { id: 3, name: 'c' }]; var filtered = _(arr).filter(function(item) { return item.id !== 3 });Can also be written as:
var filtered = arr.filter(function(item) { return item.id !== 3});var filtered = _.filter(arr, function(item) { return item.id !== 3});You can also use .reject