What it the significance of the Javascript constructor property?

Step one is to understand what constructor and prototype are all about. It's not difficult, but one has to let go of "inheritance" in the classical sense.

The constructor

The constructor property does not cause any particular effects in your program, except that you can look at it to see which function was used in conjunction with the operator new to create your object. If you typed new Bar() it will be Bar and you typed new Fooit will be Foo.

The prototype

The prototype property is used for lookup in case the object in question does not have the property asked for. If you write x.attr, JavaScript will try to find attr among x's attributes. If it cant find it, it will look in x.__proto__. If it's not there either, it will look in x.__proto__.__proto__ and so on as long as __proto__ is defined.

So what is __proto__and what has it got to do with prototype? Shortly put, prototype is for "types" while __proto__ is for "instances". (I say that with quotation marks because there's not really any difference between types and instances). When you write x = new MyType(), what happens (among other things) is that x.__proto___ is set to MyType.prototype.

The question

Now, the above should be all you need to derive what your own example means, but to try and answer your actual question; "why write something like":

Bar.prototype.constructor = Bar;

I personally have never seen it and I find it a little silly, but in the context you've given it will mean that the Bar.prototype-object (created by using new Foo(42)) will pose as have being created by Bar rather than Foo. I suppose the idea is some make something similar to C++/Java/C#-like languages where a type-lookup (the constructor property) will always yield the most specific type rather than the type of the more generic object further up in the prototype-chain.

My advice: don't think very much about "inheritance" in JavaScript. The concepts of interfaces and mixins makes more sense. And don't check objects for their types. Check for the required properties instead ("if it walks like a duck and quacks like a duck, it's a duck").

Trying to force JavaScript into a classical inheritance model, when all that it has is the prototype-mechanism as described above, is what causes the confusion. The many people that suggested to manually set the constructor-property probably tried to do just that. Abstractions are fine, but this manual assignment of the constructor property is not very idiomatic usage of JavaScript.

September 2020 Update

The answer below is from the days of ECMAScript 3 and the first sentence is no longer true because since ECMAScript 6, the constructor property is used in a few places. However, I think the overall gist still applies. Thanks to T. J. Crowder for pointing that out in the comments, and please read his answer for a fuller picture of the current situation.

Original answer

The constructor property makes absolutely no practical difference to anything internally. It's only any use if your code explicitly uses it. For example, you may decide you need each of your objects to have a reference to the actual constructor function that created it; if so, you'll need to set the constructor property explicitly when you set up inheritance by assigning an object to a constructor function's prototype property, as in your example.

one case to use constructor:

1. this is one of the common realization of inheritance:

   Function.prototype.extend = function(superClass,override) {    var f = new Function();    f.prototype = superClass.prototype;    var p = this.prototype = new f();    p.constructor = this;    this.superclass = superClass.prototype;    ...};

2. this new f() would not call the constructor of superClass,so when you create a subClass,maybe you need call the superClass at first,like this:

   SubClass = function() {    SubClass.superClass.constructor.call(this);};

so the constructor property make sense here.