RegEx that will match the last occurrence of dot in a string
You do not need a regex for this. String.lastIndexOf
will do.
var str = 'tro.lo.lo.lo.lo.lo.zip';var i = str.lastIndexOf('.');if (i != -1) { str = str.substr(0, i) + "@2x" + str.substr(i);}
Update: A regex solution, just for the fun of it:
str = str.replace(/\.(?=[^.]*$)/, "@2x.");
Matches a literal dot and then asserts ((?=)
is positive lookahead) that no other character up to the end of the string is a dot. The replacement should include the one dot that was matched, unless you want to remove it.
Just use special replacement pattern $1
in the replacement string:
console.log("tro.lo.lo.lo.lo.lo.png".replace(/\.([^.]+)$/, "@2x.$1"));// "tro.lo.lo.lo.lo.lo@2x.png"
You can use the expression \.([^.]*?)
:
str.replace(/\.([^.]*?)$/, "@2x.$1");
You need to reference the $1
subgroup to copy the portion back into the resulting string.